??? Error using ==> double Too many input arguments.

>> syms x t
total = 0;
totalmax = 0;
trest = 0;
t2 = 0;
ton = 0;
h = 0;
pulse = 1;
totaltime = 1440;
p = 5.119*exp(-0.08898*h)+ 13.47*exp(-0.0003734*h);
while pulse <= 1440
while total >= totalmax
for trest=0:totaltime
ton = (totaltime - trest)/pulse;
for i=1:pulse
t2 = double(solve(5.119*exp(-0.08898*t)+ 13.47*exp(-0.0003734*t)-p,'t'));
p = (5.119*exp(-0.08898*(t2+ton))+ 13.47*exp(-0.0003734*(t2+ton)) + 0.05262*trest);
total = total + double(int(5.119*exp(-0.08898*x)+13.47*exp(-0.0003734*x)),x,t2,t2+ton);
end
if total >= totalmax
totalmax = total;
else
trest = trest + 0,01;
if trest == 20
print trest;
end
end
end
pulse = pulse + 1;
print pulse;
end
end

Hi everybody, I seem to be running into trouble where I do the integration, I haven't got a clue how to solve this error though as it seemed to work just fine when I used numerical data for ton and trest.

Please, release me from my misery :D

Answer 1

[Walter Roberson]

Your line

total = total + double(int(5.119*exp(-0.08898*x)+13.47*exp(-0.0003734*x)),x,t2,t2+ton);

should be

total = total + double(int(5.119*exp(-0.08898*x)+13.47*exp(-0.0003734*x),x,t2,t2+ton));

[Bart]

Shouldn't try to write code so late in the evening :D

[Kevin Holst]

you beat me to it!

Answer 2

[Kevin Holst]

 total = total + double(int(5.119*exp(-0.08898*x)+13.47*exp(-0.0003734*x)),x,t2,t2+ton);

Your parentheses are incorrect here. I assume x,t2,t2+ton are parameters for int, they're being input into double (which only wants one input). try:

 total = total + double(int(5.119*exp(-0.08898*x)+13.47*exp(-0.0003734*x),x,t2,t2+ton));