How to make bode plot of transfer function

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Mike Zylla
Mike Zylla 2016년 4월 15일
댓글: Anjali 2025년 4월 2일
Hello, i am trying to make a bode plot of the transfer function of a twin-t notch filter, that i am analyzing. I was able to produce the transfer function, and the bode plot by hand, but i am struggling to do it in Matlab, here is what i have so far:
r=320; %Resistance
c=100*10^-9; %Capactiance
p=(1/(r.*c)); %Beta
a=0.95; %Signma, adjusts the wiper of a potentiometer
f=(5000); %Target Frequency
s= (1i*f);
h=((s^2 + p^2) ./ (s^2+4*p*s*(1-a)+p^2)); %Transfer function
mh=abs(h); %Magitude of h
ah=angle(h); %Phase angle of h, in rads.
I am trying to plot the body function, and here is one i made for the transfer function H=2/(s+1):
% Example Transfer Function: g(s) = 2/(s+1)
% Numerator num = [2]; % Denominator den = [1 1];
% Transfer Function G = tf(num, den)
% Plot Frequency Response bode(G), grid
My question is, how would i represent the numerator and the denominator, since they are both powers of of s, which from my understanding the computer understands as s=jw, and thus i solved the transfer function as such. I have tried to understand how exactly the bode function takes it inputs, but i am not understanding that...
Any help would be great!!!
Thanks, Mike
  댓글 수: 4
Sam Chak
Sam Chak 2024년 4월 11일
@Harsh, No error at line 6, if you run exactly the same code. Unless, you defined something else at lines 2 and 4.
% Numerator % Line 1
num = [2]; % Line 2
% Denominator % Line 3
den = [1 1]; % Line 4
% Transfer Function % Line 5
G = tf(num, den) % Line 6
G = 2 ----- s + 1 Continuous-time transfer function.
% Plot Frequency Response
bode(G), grid
Anjali
Anjali 2025년 4월 2일

openExample('control/TransferFunctionModelWithInheritedPropertiesExample')

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Star Strider
Star Strider 2016년 4월 15일
Your transfer function would use:
num = [1 0 p^2];
den = [1 4*p*(1-a) p^2];
I’m certain you can take it from there.
Also, remember that the bode function can output the results of its computations, and the bodeplot function allows you to tweak its behaviour.
  댓글 수: 6
Prasad Adavi
Prasad Adavi 2022년 10월 19일
r=320; %Resistance
c=100*10^-9; %Capactiance
p=(1/(r.*c)); %Beta
a=0.95; %Signma, adjusts the wiper of a potentiometer
f=(5000); %Target Frequency
s= (1i*f);
%h=((s^2 + p^2) ./ (s^2+4*p*s*(1-a)+p^2)); %Transfer function
num = [1 0 p^2];
den = [1 4*p*(1-a) p^2];
h=tf(num,den)
bode(h), grid
Star Strider
Star Strider 2022년 10월 19일
Easier —
r=320; %Resistance
c=100*10^-9; %Capactiance
p=(1/(r.*c)); %Beta
a=0.95; %Signma, adjusts the wiper of a potentiometer
f=(5000); %Target Frequency
% s= (1i*f);
s = tf('s');
h=((s^2 + p^2) / (s^2+4*p*s*(1-a)+p^2)); %Transfer function
% num = [1 0 p^2];
% den = [1 4*p*(1-a) p^2];
% h=tf(num,den)
bode(h), grid
.

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