Storing data from a for loop in a matrix

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CJ
CJ 2016년 4월 7일
댓글: Ced 2016년 4월 7일
Just getting started with Matlab and am running into some issues. I need to store the ouput from each step of the For Loop in a matrix. The following is my code:
% Set initial paramters.
Cl_initial=3;
R=0.5;
u=0.5;
Clt=0;
% Solve for Cl residual.
for t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54];
Clt=[t; Cl_initial*(1-R)/(1-R*exp(-u*t))];
end
The way I have it set up now only saves the very last calculation in the matrix. Any help would be appreciated!

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Ced
Ced 2016년 4월 7일
편집: Ced 2016년 4월 7일
Hi
There is a search feature in the forum, you will find hundreds of examples for this.
But your problem is that you are overwriting Clt in each iteration. The solution is to save each iteration in a new column (or row). Generally speaking, it is always good to pre-initialize data containers (in this case a matrix) before filling it in a loop.
Something like:
% Set initial paramters.
Cl_initial=3;
R=0.5;
u=0.5;
t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54];
Nt = length(t);
Clt = zeros(2,Nt);
% Solve for Cl residual.
for i = 1:Nt
Clt(:,i) = [ t(i) ; Cl_initial*(1-R)/(1-R*exp(-u*t(i)))];
end
  댓글 수: 2
Ced
Ced 2016년 4월 7일
Sure. You can "accept" the answer to close the topic if your problem was solved. Thanks!

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추가 답변(1개)

Azzi Abdelmalek
Azzi Abdelmalek 2016년 4월 7일
Cl_initial=3;
R=0.5;
u=0.5;
Clt=[];
% Solve for Cl residual.
for t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54]
Clt=[Clt;t Cl_initial*(1-R)/(1-R*exp(-u*t))]
end

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