Hi i am getting Index out of bounds error pls help me solve it
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I hv a 2d image of 93×58 pixels. Error im gettin is attempted to access b(1,59) because size(b)=(93,58).
How do i go about rectifying this error?? Pls help as im new to matlab and to image processing. Thanks in advance.
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Star Strider
2016년 3월 31일
편집: Star Strider
2016년 4월 1일
You’re asking for column 59 of a 58-column matrix.
Think about it ...
EDIT — Seeing only the part of your code that you posted (about 8 hours ago), I would simply reverse the values of ‘m2’ and ‘n2’ in your loops.
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Star Strider
2016년 4월 4일
In these lines:
m2 = m1*ms;
n2 = n1*ms;
the ‘ms’ variable has to be greater than 0 and less than or equal to 1 for that to work correctly.
The only way I can come up with to avoid addressing outside the dimensions of your image is with something like this:
m2 = fix(max(1,m2));
m2 = fix(min(m1,m2));
n2 = fix(max(1,n2));
n2 = fix(min(n1,n2));
That limits the index variables to the limits of your image size.
추가 답변 (2개)
MHN
2016년 3월 31일
So, you should not attempt to get b(1,59) when the size of b is (93,58) !!!
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Walter Roberson
2016년 4월 1일
Consider the possibility that you have m2 and n2 exchanged in your code.
Another possibility: did you use
[m2, n2] = size(YourMatrix)
and your image is a color image? If so then you have a bug because of the way that size() is defined when you have fewer outputs than the array has dimensions. Instead use
[m2, n2, ~] = size(YourMatrix)
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