delete first x number of rows from a cell array

I have a 2000*4 cell array. The 4th column is an ascending numeric values from 0 to 30. I do not know how many rows have 0 value in 4th column, and I would like to delete those rows from cell array. I wrote the following code with the loop, which works well. But is there any efficient way to avoid the for-loop?

[m,n]=size(A);
count = 0;
for i=1:m
    if isequal(A{i,4},0)
        count = count+1;
    end
end
A = A(count+1:m,:)

Thank you in advance

Answer 1

[Stephen23]

>> C =  num2cell([randi(9,6,3),[0;0;0;1;2;3]])
C = 
    [5]    [8]    [6]    [0]
    [2]    [3]    [5]    [0]
    [2]    [9]    [4]    [0]
    [3]    [4]    [8]    [1]
    [8]    [2]    [6]    [2]
    [3]    [3]    [5]    [3]
>> C([C{:,4}]>0,:)
ans = 
    [3]    [4]    [8]    [1]
    [8]    [2]    [6]    [2]
    [3]    [3]    [5]    [3]

Answer 2

[Jos (10584)]

Each cell in the 4th row of A should contain a scalar, being 0 or another value

tf = [A{:,4}] ~= 0 
Aout = A(tf,:)

[Shima Asaadi]

Many thanks, it worked.