How to put a function in another function?

For instance, if there are two functions which are with respect to x: f(x) = x^2 and g(x) = 4*x, I want to make another function using them: h(x) = (f(x)+5*g(x))/(2*f(x)*g(x))

But,

f = @(x) x^2;
g = @(x) 4*x;
h = @(x) (f+5*g)/(2*f*g);

doesn't work.

Is there any way to do this?

Answer 1

[Geoff Hayes]

Yusuke - if x is the input parameter to your function h, then you must pass this into f and g as well. So instead of

 h = @(x) (f+5*g)/(2*f*g);

you would write

 h = @(x) (f(x)+5*g(x))/(2*f(x)*g(x));

Try the above and see what happens!

[Yusuke Nakamura]

Thanks! It worked!!

Answer 2

[the cyclist]

You have to supply the function arguments:

h = @(x) (f(x)+5*g(x))/(2*f(x)*g(x));

[Yusuke Nakamura]

Thanks!!