Dividing a scalar by a vector

I understand that in order to divide a scalar, say a, by a vector, say b, I need to use the following syntax: c = a./b. But what if b was defined as [2 0]? The zero in b causes c to go to Inf and this disrupts my plot. Is there a way to get around this?

[Walter Roberson]

What would you like to have happen there?

[VENKATESAN SEETHARAMAN]

MATLAB generates a completely blank plot. I am assuming the division by 0 is the cause of the blank plot. Please correct me if I am wrong.

[Stephen23]

@VENKATESAN SEETHARAMAN: You are wrong. The plot contains exactly one point, this being the finite value that you have given to plot. Here it is:

>> V = 1./[0,2]
V =
          Inf          0.5
>> H = plot(V,'xr');

And we can even check the values in the plot:

>> get(H,'Ydata')
ans =
          Inf          0.5

So you are wrong that "MATLAB generates a completely blank plot", because it has actually plotted exactly the data that you have given it. You requested a plot of one finite point and that is what you get.