removing zeros from matrix

Hi,

I have a matrix like this:

0 0 2 3 4 0;
1 0 2 0 0 1;
3 2 1 0 0 0;
0 1 0 3 0 1;

I want to remove the zeros so I could have something like this:

2 3 4;
1 2 1;
3 2 1;
1 3 1;

The number of zeros in each row of the original matrix is the same. Any idea how can I do this? Commands like A=A(A ~= 0) didn't work.

Thanks!

Answer 1

[Roger Stafford]

 A = A.';
 A = reshape(A(A~=0),3,4).';

[Mahmoud Zeydabadinezhad]

Hi Roger, Can you please elaborate how did you come up with this solution? and what is A. ?

Thank you!

[Image Analyst]

Take it a step at a time and use intermediate variables and get rid of the semicolons so the result goes to the command window:

A=[0 0 2 3 4 0; 1 0 2 0 0 1; 3 2 1 0 0 0; 0 1 0 3 0 1]
Atransposed = A.'
vectorNoZeros = Atransposed(Atransposed ~= 0)
reshapedVector = reshape(vectorNoZeros,3,4).'

You'll see this, which hopefully explains it well enough:

A =
     0     0     2     3     4     0
     1     0     2     0     0     1
     3     2     1     0     0     0
     0     1     0     3     0     1
Atransposed =
     0     1     3     0
     0     0     2     1
     2     2     1     0
     3     0     0     3
     4     0     0     0
     0     1     0     1
vectorNoZeros =
     2
     3
     4
     1
     2
     1
     3
     2
     1
     1
     3
     1
reshapedVector =
     2     3     4
     1     2     1
     3     2     1
     1     3     1

Answer 2

[Azzi Abdelmalek]

 v=[0 0 2 3 4 0; 1 0 2 0 0 1; 3 2 1 0 0 0; 0 1 0 3 0 1]
out=reshape(v(v~=0),size(v,1),[])

Answer 3

[Image Analyst]

This works:

A=[0 0 2 3 4 0; 1 0 2 0 0 1; 3 2 1 0 0 0; 0 1 0 3 0 1]
for row = 1 : size(A, 1)
  thisRow = A(row,:)
  % Remove zeros
  thisRow(thisRow == 0) = [];
      % Append to new matrix.
  if row == 1
    Anozeros = thisRow
  else
    Anozeros = [Anozeros; thisRow];
  end
end
A = Anozeros

I'm sure there are other ways too. (Hopefully it's not homework, though it looks like it.)

[Mahmoud Zeydabadinezhad]

No worries. It's not a homework!