Binary sequence from a vector to a variable

Hi!I have a binary sequence and I want to save it in a variable. How could I do it? Like this:

a= [1,0,0,1,0] -> ? -> b=10010

Thank you very much

Answer 1

[Ced]

But a IS the binary sequence save in a variable? If you want to transform this into some decimal representation of the same digits...

represent_bin_as_dec = @(x)sum(x.*10.^(length(x)-1:-1:0),2);

a = [ 1 0 0 1 0 ];
b = represent_bin_as_dec(a)

Cheers

[John D'Errico]

bin2dec

[Ced]

Yep, saw the answer. Good to know, thanks!

Although I think I still prefer to stay in the number realm rather than corrupting this mathematical purity with some characters, haha.

Guillaume's answer looks cleaner than mine here... but I just like to see the inner working of things. I guess that internally, polyval does more or less the same thing, plus of course all the input parsing and such.

I always enjoy having multiple answers for the same question. That's when we really learn new things :).

Answer 2

[John D'Errico]

a already is a variable!

That sequence is a vector of information. As such, you need to store it in a vector.

1. You can convert it to a string. But it will still be a vector, just a vector of character elements. So

b = char(a+'0')
b =
10010

2. You can convert it to an integer, as long as there are not more than 64 bits of information, if you will store it in a double.

b = bin2dec(char(a+'0'))
ans =
    18

bin2dec only works up to 52 bits of course. Beyond that, you would need to use a conversion into uint64.

Answer 3

[Guillaume]

Another option

a = [1 0 0 1 0]
b = polyval(a, 10)  %decimal representation of the same digits

Note that I don't see how b is useful, since you can't use it to perform any arithmetic. The true number represented by a is:

c = polyval(a, 2)

[John D'Errico]

A nice trick for base conversions. Of course, still limited to double as such. But still nice.

Answer 4

[Cristian Mancera]

I used bin2dec, it is very simple and exactly what I needed, thanks to all of you :)

[Andrei Bobrov]

In it case, please accept answer by John D'Errico.