How to eliminate value at each position required

Hi,

I have an array of matrix in the a=cell (1,16). Each of the array matrix in the cell is equal to 128x128. Then, I did the multiplication between each of column of the cell so that I can get a pair projection of 128x128 of each matrix. I.e: E{i,j}. Thus, I will get E{1,2}, E{1,3}..till..E{16,16} and each of E{i,j} has 128x128 array matrix.

From each of the pair projection, I want to eliminate the value at certain position in the 128x128 matrix. For example, at position (31,119), (13,102), (98,10) and (11,27)in each pair projection of E{i,j}, I want the value becomes zero.

how can I write the code? Can anybody guide how to write a correct code for this function. I have tried to write the code but it consists an error.

load('EveryProjectionNormDEliminateSpike_max_same_v2.mat');

% ---------- Dot product to get each pairing projection -----------

i=1;

for i=1:16;                   
    m1=EachProj_EliminateSpike_MaxSpike_v2{1,i};

      for j=1:16
          m2=EachProj_EliminateSpike_MaxSpike_v2{1,j};
          c=m1.*m2;               % Do the element multiplication to get Ei,j
          E{i,j}=c;
      end
  end
  % eliminate position has spike equal to zero
  for i=1:16;
  for j=1:16;
      for Tx=1:128;
      for Rx =1:128;
          if E{i,j}(Rx,Tx)= E{i,j}(31,119);E{i,j}(31,119)=0;end
          if E{i,j}(Rx,Tx)= E{i,j}(98,10);E{i,j}(98,10)=0;end
      end
      end
  end
  end

Answer 1

[MHN]

for i=1:16;
for j=1:16;
    for Tx=1:128;
    for Rx =1:128;
        if E{i,j}(Rx,Tx)==E{i,j}(31,119)
             E{i,j}(31,119)=0;
        end
        if E{i,j}(Rx,Tx)==E{i,j}(98,10)
             E{i,j}(98,10)=0;
        end
    end
    end
end

[MHN]

There are more efficient way rather than 4 nested loop, but I just corrected your code.