Finding columns that contain both integers and NaN

조회 수: 3(최근 30일)
Ahmed Hamed
Ahmed Hamed 2016년 2월 4일
댓글: the cyclist 2016년 2월 4일
I have a matrix that contain Numerical values (float) and Categorical values (Int)
as
A = 1 NaN 2.2 3.2 4
NaN 7.9 5.1 NaN 5
3 5.5 NaN 4.1 NaN
and I'd like to split it into matrices;
one contains the Int values and the other contains the float values as
it = 1 4
NaN 5
3 NaN
and
flt = NaN 2.2 3.2
7.9 5.1 NaN
5.5 NaN 4.1
i use the following code
int_cols = all( round(A)==A, 1 ); %// logical indexing into integer columns
it = A(:,int_cols);
flt = A(:,~int_cols);
However, NaN isn't equal NaN so it appears in the flt matrix and it = [].
Are there any function that can help?

답변(2개)

David Young
David Young 2016년 2월 4일
Yes, isnan(x) does what x == NaN would do if NaNs were equal to each other.

the cyclist
the cyclist 2016년 2월 4일
int_cols = all( round(A)==A | isnan(A), 1 ); %// logical indexing into integer columns
it = A(:,int_cols)
flt = A(:,~int_cols)
  댓글 수: 1
the cyclist
the cyclist 2016년 2월 4일
If the entries in A are have been computed in prior operations, you might also want to guard against floating point inaccuracies, such as the value "4" actually being 4.0000000000001. You could check for equality to within a specific tolerance, for example.

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