Solving simple symbolic trigonometry equations

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John
John 2016년 1월 28일
댓글: John 2016년 2월 2일
I have a simple trigonometric equation I would like to solve, but I can't seem to get Matlab to give me an answer:
a*sin(x)-b*cos(x) = 0
I want to solve for x. This has a trivial solution and is easy to see by eye:
x = atan(b/a) and x = atan(b/a) + pi
I'd like to know whether it's possible to lead Matlab to the answer. I've tried:
syms a b x real;
solve(a*sin(x)-b*cos(x) == 0,x) % No solution
solve(a*sin(x) == b*cos(x),x) % Again, no solution
solve(a*sin(x)-b*cos(x), x) %Again no solution
All of these (and the variations I've thought of) give no solution. Any thoughts?

답변 (1개)

Vineeth Kartha
Vineeth Kartha 2016년 2월 2일
Hi John,
Use the "solve" command as follows:
>> solve(a*sin(x) == b*cos(x),x,'IgnoreProperties',true,'ReturnConditions',true);
This returns a structure expressing the full solution.
Refer to the MATLAB documentation of solve for more information.
  댓글 수: 1
John
John 2016년 2월 2일
Hmm. Thanks for your answer. I had come across that combination, which for the sake of any other readers gives:
pi*k - (log((a + b*1i)/(a - b*1i))*1i)/2
However I was really hoping to avoid complex exponentials in the the answer (it complicates subsequent manipulation). All my variables are real-valued, and carrying along the full complex form is cumbersome.

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