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How can I make all the variables in an array 0 after the first time 0 occurs in the array

조회 수: 1 (최근 30일)
I am trying to create a weighting function based on a set of criteria. When the weighting function is created, I get an array containing 1's and 0's. However, I am trying to force the array to be all 0's once the first 0 occurs.
For example: x = [1,1,1,1,1,0,0,1,1,0,0,0...] for which I would then like it to read x = [1,1,1,1,1,0,0,0,0,0,0,0...].
Any tips would be greatly appreciated.

답변 (2개)

Guillaume
Guillaume 2016년 1월 20일
A very simple solution that only works with an array of 0 and 1 starting with 1:
x = [1,1,1,1,1,0,0,1,1,0,0,0]
cumprod(x)
  댓글 수: 2
Walter Roberson
Walter Roberson 2016년 1월 21일
I find in practice that most of the time that I want to do this, I want to work row by row; in that case I need to be sure to specify the dimension number,
cumprod(x,2)
Stephen23
Stephen23 2016년 1월 21일
Without a leading one:
>> x = [0,0,1,1,1,1,1,0,0,1,1,0,0,1,0]
x =
0 0 1 1 1 1 1 0 0 1 1 0 0 1 0
>> x .* (1==cumsum(0<diff([0,x])))
ans =
0 0 1 1 1 1 1 0 0 0 0 0 0 0 0

jgg
jgg 2016년 1월 20일
Generate your x as normal, with the many 1's afterwards then call:
x = [1,1,1,1,1,0,0,1,1,0,0,0]; %generate x
x(find(x == 0,1,'first'):end) = 0

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