"converting" randit to randi

I have this function
a = randint(1,1,actions)+1;
actions = [-1, 0 ,1];
It is not working in R2013b, so I am guessing this is already an obsolete function.
I would like to 'convert' it to 'randi' function that is used here, how would this look like?
Thanks

답변 (1개)

Star Strider
Star Strider 2016년 1월 5일

0 개 추천

What do you want to do?
To create a (1x10) vector of random integers from 1 to 100, a randi call would be:
rv = randi(100, 1, 10);
to create a similar vector with random integers from 25 to 75, this works:
rv = randi([25 75], 1, 10);

카테고리

도움말 센터File Exchange에서 Random Number Generation에 대해 자세히 알아보기

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cgo
2016년 1월 5일

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2016년 1월 5일

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