Help with improfile, profile between two selected points.

Hi all,

Mine could be a really dumb question, but I'm having trouble in getting the image profile between two points. The two points should be provided by pairs of x and y coordinates, and, by using improfile or whatever function I'd like to have a 1d array of intensity points.

I've read the documentation, but this sentence is most obscure to me:

improfile(I,xi,yi) retrieves pixel intensity values, where I specifies an image, and xi and yi are equal-length vectors specifying the spatial coordinates of the endpoints of the line segments.

I really don't get what the function wants... I've tried something like:

profile = improfile(image,[1,1],[50,50])

But it returns me a number, insted of the intensity array between the two points 1,1 and 50,50....

Thanks in advance for your help.

Andrea

Answer 1

[Walter Roberson]

"image" is the primitive graphics function to create and display image objects. It would return the handle of the object. You should never use "image" as a variable name because of the risk that the MATLAB function might be referred to instead.

[Andrea Calvi]

Thanks, I didn't know of that! Anyway I simply changed the name of my variables for the purpose of posting here.

[Walter Roberson]

profile = improfile(TheImage,[1,50],[1,50])

[Image Analyst]

Andrea, you can "Accept this answer" (and your prior ones) to let people know it's been solved and to give the person who helped you credit (reputation points).

Answer 2

[Anuj Prajapati]

If you're improfiling a matlab .fig file, auto improfiling like improfile(I,xi,yi) will return a null graph, while freehand manual improfiling will give you results. If you save the .fig file as an image like .tiff, it will generate an RGB separated graph.

[Walter Roberson]

This sounds suspicious. Could you post code to reproduce this behaviour for .fig files?