how can i take a variable which store decimal values

I am having problem to store decimal value. whenever i am taking greater denominator value it shows only zero . please can any one help me asap

[dpb]

Well, from just the description we don't know precisely what operation you mean by "[I} am taking greater denominator value". Show us code and input.

Answer 1

[Walter Roberson]

If you have variables A, B, that are members of one of the integer classes, such as uint8 or int16, then when you divide A/B the result is defined to be the same as

cast(double(A)/double(B), class(A))

That is, a fraction will be calculated but the result will be made back into the original data type. The process of converting a floating point value to an integer data type is defined to be done by rounding. uint8(159.3) rounds to uint8(159), uint8(159.6) rounds to uint8(160) .

Therefore if you have two integer variables, A/B and B > A, then the result will come out as either 0 or 1 depending on which way the fraction double(A)/double(B) rounds. In particular for A/B with B from A up to and including 2*A will round to 1, and A/B with B > 2*A will round to 0.

If this is a problem then you should either not be using integer class variables or you should be converting the values to double before doing the division, double(A)/double(B) so that the result is not converted back to class(A).

Note: It isn't exactly class(A) that is used in practice but it only makes a difference if you start mixing double and integer class in an operation.

[Madhu]

x = 195

fd = 2

y = x./fd

i am getting the value as 98

but i need the value as decimal as 97.2

what can i do/

please anyone help me

[John D'Errico]

@Madhu

your number is an INTEGER. Dividing it by 2 yields another integer.

x = uint8(195)

x = uint8 195

y = x/2

y = uint8 98

class(y)

ans = 'uint8'

You need to convert it to a double FIRST.

z = double(x)/2

z = 97.5000