When I try to run the following parfor loop, Matlab returns the error claiming that A cannot be classified.
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
for t = 1:1:T
A(i,t) = rand(1,1);
end
end
Why isn't A considered to be a sliced output variable? The following modification works just fine.
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
A(i,1) = rand(1,1);
end
So it seems to be something to do with the inner loop over t. From reading the help document on sliced variables, I don't understand why this inner loop would make a difference.

댓글 수: 2

even coil
even coil 2015년 12월 11일
Is there a workaround besides using the vectorized version of rand? (Doing the analgous would be difficult in the application I have in mind.)
Matt J
Matt J 2015년 12월 11일
편집: Matt J 2015년 12월 11일
If you interchange the order of the loops you've shown, it will run. Whether that's the best solution is hard to tell, though, without seeing an example closer to the application you have in mind.

댓글을 달려면 로그인하십시오.

 채택된 답변

Edric Ellis
Edric Ellis 2015년 12월 11일

1 개 추천

In this case, the fix is simply to remove the increment from the inner for loop, like so:
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
for t = 1:T
A(i,t) = rand(1,1);
end
end
(I'm not sure why this limitation exists, it doesn't appear to be explicitly mentioned in the documentation)

댓글 수: 3

Matt J
Matt J 2015년 12월 11일
편집: Matt J 2015년 12월 11일
(I'm not sure why this limitation exists, it doesn't appear to be explicitly mentioned in the documentation)
Maybe for the same reasons that this isn't supported:
parfor i = 1:1:N
for t = 1:i:T
A(i,t) = rand(1,1);
end
end
If A isn't pre-allocated, I can see parfor having a hard time figuring out what size(A) should ultimately be.
even coil
even coil 2015년 12월 11일
Why isn't this considered a bug? Isn't "1:T" just shorthand for "1:1:T"?
Matt J
Matt J 2015년 12월 11일
편집: Matt J 2015년 12월 11일
Hard to say if it can be called a bug because it's not yet clear what level of support is intended for nested loops that interact with sliced variables. Note, for example, that the following also produces a classification error,
parfor i = 1:1:N
for t = 1:2:T
A(i,t) = rand(1,1);
end
end

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Walter Roberson
Walter Roberson 2015년 12월 11일

1 개 추천

N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
v = zeros(1,T);
for t = 1:1:T
v(1,t) = rand(1,1);
end
A(i, :) = v;
end

카테고리

도움말 센터File Exchange에서 Resizing and Reshaping Matrices에 대해 자세히 알아보기

태그

질문:

2015년 12월 10일

편집:

2015년 12월 11일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by