why imerode and imdilate make matlab stopped every time ?

조회 수: 6 (최근 30일)
alaa adel
alaa adel 2015년 12월 8일
댓글: Walter Roberson 2015년 12월 10일
after write imerode function
i=imread('\cameraman.jpg');
B=im2bw(1,0.3);
K3=ones(3);
K5=ones(5);
K7=ones(7);
K9=ones(9);
B3=imerode(B,K3);
B5=imerode(B,K5);
B7=imerode(B,K7);
B9=imerode(B,K9);
imshow(B)
figure, imshow(B3), title('by 3');
figure, imshow(B5), title('by 5');
figure, imshow(B7), title('by 7');
figure, imshow(B9), title('by 9');
matlab stop and popup msg with matlab must be debug ?
what can i do ?
function imdilate show msg matlab has encountered an internal problem and need to close .
so how solve this problem ?
  댓글 수: 2
Walter Roberson
Walter Roberson 2015년 12월 8일
Does your MATLAB also stop working as soon as you draw any graphics? For example, does plot(3,5) cause problems?
Amith Kamath
Amith Kamath 2015년 12월 8일
FYI: The crash can be observed by doing this:
imerode(true, ones(3,3));
There is no crash observed for other strel sizes.

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Amith Kamath
Amith Kamath 2015년 12월 8일
Alaa:
You've probably found a bug in imerode. However, I believe you really meant to do this instead:
B = im2bw(i, 0.3); % in this case, B is indeed the 256x256 matrix.
rather than
B = im2bw(1,0.3); % in this case, B is a scalar logical value of 1.
Doing so will not make MATLAB crash, but provide you the results you were originally looking for.
Hope this helps!
  댓글 수: 2
alaa adel
alaa adel 2015년 12월 9일
편집: Walter Roberson 2015년 12월 10일
thank you for your help
this
B= im2bw(i);
solve my problem as not make MATLAB crash
but i don't know the reason
Walter Roberson
Walter Roberson 2015년 12월 10일
This is one of the reasons to avoid using i as a variable name.

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