How to use who within eval

조회 수: 2 (최근 30일)
Qianyu
Qianyu 2012년 1월 9일
편집: per isakson 2017년 2월 16일
Here is the code:
file_name = 'test';
eval(['file_length = length(who(''-file'',' file_name '));']);
But this doesn't work, because who requires a quoted string as a variable. Then I tried this,
eval(['file_length = length(who(''-file'', ''file_name'' ));']);
It didn't work, apparently. Now file_name showed up instead of the value I put in it. This sounds a very simple question, but I just don't know what to do. Help!

채택된 답변

Andrew Newell
Andrew Newell 2012년 1월 9일
This is a working example:
clear
x = zeros(10,1); y = x;
save matlab.mat
file_name='matlab.mat';
eval('file_length = length(who(''-file'',file_name))')
file_length =
2
EDIT: Although I answered the question you asked, I agree with Sean and the Cyclist that it would be better not to use eval. See Loren's blog for some reasons.
  댓글 수: 3
Andrew Newell
Andrew Newell 2012년 1월 9일
Actually, the Cyclist's solution would also work nicely in a loop.
the cyclist
the cyclist 2012년 1월 10일
For example, even if you need the value of the looping variable in the file name, you can often use num2str() to convert the numeric to a string, and append it to the file name.

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추가 답변 (2개)

Sean de Wolski
Sean de Wolski 2012년 1월 9일
Why use eval? Nothing in that statement looks like it couldn't be done without it.

the cyclist
the cyclist 2012년 1월 9일
Agree with Sean that you do not need eval() here. Try this:
file_name = 'test';
file_length = length(who('-file',file_name));

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