Array division giving incorrect answer?
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Hello, I am working on a code that reads in an excel sheet and creates arrays from the columns. These arrays are then manipulated together as seen below.
if true
filename = 'Book1.xlsx';
n = xlsread(filename,'B:B');
hour_angle = xlsread(filename,'D:D');
lat = 40;
slope = 32;
azimuth_angle=0;
declination=23.45*sind(360/365*(284+n));
cos_angleofincidence=sind(declination).*sind(lat).*cosd(slope)-sind(declination).*cosd(lat).*sind(slope).*cosd(azimuth_angle)+cosd(declination).*cosd(lat).*cosd(slope).*cosd(hour_angle)+cosd(declination).*sind(lat).*sind(slope).*cosd(azimuth_angle).*cosd(hour_angle)+cosd(declination).*sind(slope).*sind(hour_angle);
cos_zenithangle=cosd(lat).*cosd(declination).*cosd(hour_angle)+sind(lat).*sind(declination);
Rb=cos_angleofincidence./cos_zenithangle
end
(To simplify my explanation, I am just going to use the last number in the array as an example)
From cos_angleofincidence, the last number in the array is given as -0.9655. The last number in cos_zenithangle comes out to be -0.9567. As I understand it, Rb should have them dividing as an array because of the "./", so it should be -.9655/-.9567. The answer I get instead is 0.0010.
If I leave all lines in the code the same, but change Rb to look at only that last couple as below:
if true
% code
Rb=cos_angleofincidence(8760)./cos_zenithangle(8760)
end
I instead get an answer of Rb = 1.0092 for said couple (which is the answer I am looking for).
Can anyone please explain what is going on? I really don't understand what is changing between the two. I would really appreciate any help you guys can give.
Thank you so much!
Caitlin
댓글 수: 2
Image Analyst
2015년 11월 22일
Are you sure you're not overlooking a 1e3 in the display somewhere? Please attach book1.xlsx so we can run your code.
ck120812
2015년 11월 22일
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