Hi everybody, I want different scenarios of a vector with 0 and 1 elements. For example v=[0 0 0 0 0 0 0], v=[0 1 0 1 0 1 0 ] , v=[0 1 1 1 1 1 1] and so on. But the first element of vector is fixed and has be zero .

조회 수: 1 (최근 30일)
Hi everybody, I want different scenarios of a vector with 0 and 1 elements. For example v=[0 0 0 0 0 0 0]. v=[0 1 0 1 0 1 0 ] ,v=[0 1 1 1 1 1 1] and so on. But the first element of vector is fixed and has be zero

채택된 답변

Guillaume
Guillaume 2015년 11월 9일
"Thank you very much. But I need all 64 different scenarios."
You should have asked that to start with.
Your example uses 7 bits, that would be 128 different scenarios, if you vary all the bits. Regardless, to get the first 64 binary numbers
dec2bin(0:63, 7) - '0'

추가 답변 (2개)

arich82
arich82 2015년 11월 9일
Use dec2bin with its second argument:
>> n = 6;
>> a = dec2bin(0:2^n-1, n+1)
a =
0000000
0000001
0000010
0000011
0000100
0000101
0000110
0000111 ...
[remaining output elided]
Note that this returns a char array. If you need an array of doubles, you can "cheat" to convert it by subtracting the string '0':
a = dec2bin(0:2^n-1, n+1) - '0';
Alternatively, you can use bitget, wrapped inside a call to bsxfun:
a = bsxfun(@bitget, [0:2^n-1].', n+1:-1:1);
Please accept this answer if it helps, or let me know in the comments if I missed something.
  댓글 수: 3
Guillaume
Guillaume 2015년 11월 9일
You can only accept one answer. Once you've accepted an answer you can't change your mind (as far as I know).
You can still vote for arich82's answer (click on the grey triangle next to the answer) to give him reputation points.
arich82
arich82 2015년 11월 9일
Guillaume's answer is essentially the same, and he submitted 4 minutes earlier while I was still typing; he should get the accepted answer. I'll leave mine here in case someone wants to reference the bitget solution.

댓글을 달려면 로그인하십시오.


Thorsten
Thorsten 2015년 11월 9일
x = [0 rand(1,6) > 0.5];

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by