How to compare string elements within a cell?

조회 수: 1 (최근 30일)
travis etter
travis etter 2015년 10월 24일
편집: Jan 2015년 10월 24일
Trying extract each string from a cell and then make a comparison of each element of that string. Currently this is what i have up until where im getting the error when im trying to compare each element in the if statement. The way i am reading my code the 1st time through my the 1st for loop is assigning input2 as the first indicie of input 'dog'. Then it enters my 2nd for loop looking at each indice of input2 ('dog') then making a comparison in the if statement. Where am i going wrong in this?
input = {'dog','cat','string'};
output = cell(size(input,1),size(input,2));
for k = 1:length(input)
input2 = input{k};
for i = 1:length(input2)
if input2(i) == 'a'||input2(i) == 'e'||input(i) == 'i'||input(i) == 'o'||input(i) == 'u'
out(i) = input2(i) + 3
else
out(i) = input2(i) + 5
end
end
output{k} = out
end

답변 (1개)

Jan
Jan 2015년 10월 24일
편집: Jan 2015년 10월 24일
You used "input" instead of "input2" in the if condition:
if input2(i) == 'a'||input2(i) == 'e'||input(i) == 'i'||input(i) == 'o'||input(i) == 'u'
better:
if input2(i) == 'a'||input2(i) == 'e'||input2(i) == 'i'||input2(i) == 'o'||input2(i) == 'u'
nicer:
if any(input2(i) == 'aeiou')
A complete function:
inputC = {'dog','cat','string'}; % "input" is a built-in function!
outputC = cell(size(inputC));
for k = 1:numel(inputC) % Safer then LENGTH
inputS = inputC{k};
match = ismember(inputS, 'aeiou');
outputS = inputS + 5;
outputS(match) = inputS(match) + 3;
outputC{k} = outputS;
end

카테고리

Help CenterFile Exchange에서 String Parsing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by