Switch case and matrix input

조회 수: 8 (최근 30일)
Nicholas Carlson
Nicholas Carlson 2015년 10월 18일
댓글: Stephen23 2022년 10월 17일
n = input('number of rows \n ')
for d = (1:n)
Month = {'Mar'}
Days = cell(n,1);
switch Month
case {'Jan'}
Days = Total_Days(d,1) +6;
case {'Feb'}
Days = Total_Days(d,1) - 24;
case {'Mar'}
Days = Total_Days(d,1) - 53;
case {'Apr'}
Days = Total_Days(1:end,1) - 84;
case {'May'}
Days = Total_Days(1:end,1) - 114;
case {'Jun'}
Days = Total_Days(1:end,1) - 145;
case {'Jul'}
Days = Total_Days(1:end,1) - 175;
case {'Aug'}
Days = Total_Days(1:end,1) - 206;
case {'Sep'}
Days = Total_Days(1:end,1) - 237;
case {'Oct'}
Days = Total_Days(1:end,1) - 267;
case {'Nov'}
Days = Total_Days(1:end,1) - 298;
case {'Dec'}
Days = Total_Days(1:end,1) - 328;
case {'Ja_'}
Days = Total_Days(1:end,1) - 359;
Actual_Year = Actual_Year + 1;
end
end
My code runs with an error shown like this.
SWITCH expression must be a scalar or string constant.
Error in Setting_Date_New (line 33)
switch Month
I need the answer to be in a matrix form that can compute with multiple sets of months at a time.
  댓글 수: 2
FM
FM 2022년 10월 17일
It sure would be helpful if the documentation specified that the switch expression must be a scalar.
Stephen23
Stephen23 2022년 10월 17일
"It sure would be helpful if the documentation specified that the switch expression must be a scalar."
It does. The SWITCH documentation states "An evaluated switch_expression must be a scalar or character vector. An evaluated case_expression must be a scalar, a character vector, or a cell array of scalars or character vectors."

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답변 (1개)

the cyclist
the cyclist 2015년 10월 18일
It's not clear to me what you are trying to do, but if you replace
Month = {'Mar'}
with
Month = 'Mar'
you will at least get past your current error.

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