Hi , I know this is very simple, I have a matrix looks like
A =
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
I need to select the rows which contains only one 1's like the rows 1,2,4. next i need to select the rows which contains two ones like the rows 3,5,6.I'm using the function find to check the indexes containing one as follows:
for i=1:length(A)
b=find(A(i,:)==1);
c(i)=length(b);
end
Is there any possible solution instead of using the for loop, because I need to use this code for the similar matrix contains 120 columns? Thanks for the help.

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Star Strider
Star Strider 2015년 10월 13일

0 개 추천

This works:
A = [0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1];
Rows_1 = find(sum(A,2)==1) % Rows with 1 ‘1’
Rows_2 = find(sum(A,2)==2) % Rows with 2 ‘1’s
Rows_3 = find(sum(A,2)==3) % Rows with 3 ‘1’s

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Naga A
Naga A 2015년 10월 13일
Thank you.
Star Strider
Star Strider 2015년 10월 13일
My pleasure.

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도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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