Help with code: Matlab code not printing last verification line.
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I can't get Matlab to print the last "data within tolerance" line:
function [integral] = intmidpoint(N)
clear
clc
%INTMIDPOINT numerical integration using the composite midpoint rule
clc
%define the integration limits
a=0;
b=2;
%this is the aim of absolute error required
aim = 0.001;
%define the number of sub-intervals to be used
if nargin == 1
n=N;
else
n=1;
end
h=(b-a)/n;
%approximate integral using the composite mid-point rule
integral=0.0;
%add the contribution of each sub-interval in turn
abs_err = realmax;
while abs_err>aim;
h=(b-a)/n;
integral=0.0;
for i=1:n;
x_left = a+(i-1)*h;
x_right = a+i*h;
x_half = (x_left+x_right)/2.0;
f_half = f(x_half);
integral = integral+h*f_half;
abs_err=abs(4-integral);
end;
fprintf('2 Midpoint approximation to integral using %g subintervals is %g. \n Data outside of tolerance. Abosolute error is %g, which is greater than 0.001. Increase the number of steps. \n',n,integral,abs_err);
n = n + 1;
if abs_err>aim;
continue;
fprintf('test Midpoint approximation to integral using %g subintervals is %g. \n Data within tolerance. Absolute error is %g, which is less than 0.001. \n',n,integral,abs_err);
end;
end;
end
%subfunction defines the integrand
function [f_value] = f(x)
f_value = (x)^3;
end
댓글 수: 0
답변 (1개)
Walter Roberson
2015년 10월 12일
The "continue" is going to be executed before the fprintf() that is in the same "if"
댓글 수: 4
Geoff Hayes
2015년 10월 12일
Try this
if abs_err>aim
fprintf('test Midpoint approximation to integral using %g subintervals is %g. \n Data within tolerance. Absolute error is %g, which is less than 0.001. \n',n,integral,abs_err);
break;
end
Note that the
ans =
3.9990
is the output parameter returned from your function call. You are probably calling your function from the command line without assigning the output to a variable. Try calling your function as
[estIntegral] = intmidpoint(42);
to suppress the extra output. (Note that it is the use of the semi-colon that is suppressing the output.)
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