Tic Tac Toe Win Checking Function

조회 수: 7 (최근 30일)
Anas Abou Allaban
Anas Abou Allaban 2015년 10월 2일
댓글: Anas Abou Allaban 2015년 10월 3일
I'm writing a tic tac toe game and part of the 'coding rules' is that there should be a 'checkwin' function to see whether a player has won or not. I have defined two variables called 'tttXArray' and 'tttOArray' to see whether one player has gotten three in a row for horizontal, vertical, or diagonal inputs. This is the function with the tttXArray placed as an example:
function [won] = checkwin
%Check to see whether the game has been won or not
% Horizontal
if (tttXArray(1,1) == tttXArray(1,2) && tttXArray(1,1) == tttXArray(1,3))
won = 1;
elseif (tttXArray(2,1) == tttXArray(2,2) && tttXArray(2,1) == tttXArray(2,3))
won = 1;
elseif (tttXArray(3,1) == tttXArray(3,2) && tttXArray(3,1) == tttXArray(3,3))
won = 1;
% Vertical
elseif (tttXArray(1,1) == tttXArray(2,1) && tttXArray(1,1) == tttXArray(3,1))
won = 1;
elseif (tttXArray(1,2) == tttXArray(2,2) && tttXArray(1,2) == tttXArray(3,2))
won = 1;
elseif (tttXArray(1,3) == tttXArray(2,3) && tttXArray(1,3) == tttXArray(3,3))
won = 1;
% Diagonal
elseif (tttXArray(1,1) == tttXArray(2,2) && tttXArray(1,1) == tttXArray(3,3))
won = 1;
elseif (tttXArray(1,3) == tttXArray(2,2) && tttXArray(1,3) == tttXArray(3,1))
won = 1;
end
end
The error I get is:
Undefined function 'tttXArray' for input arguments of type 'double'.
What seems to be the problem?

채택된 답변

John D'Errico
John D'Errico 2015년 10월 2일
Your function has no arguments. How do you expect it to know what those variables are?
  댓글 수: 6
Thorsten
Thorsten 2015년 10월 2일
No. You should define
function won = checkwin(tttXArray)
and call using
checkwin(tttXArray)
Anas Abou Allaban
Anas Abou Allaban 2015년 10월 3일
So I realized my rather beginner mistake, I was not calling the function properly nor was I giving it any proper arguments. The checkwin function works good now, time to debug the rest of the code. Thanks Thorsten for the simplified checking algorithm!

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