Gerchberg–Saxton algorithm

조회 수: 23 (최근 30일)
maria
maria 2015년 9월 27일
댓글: Isaac Oguntoye 2018년 5월 31일
Hello! I have the following code:
for k=1:1:20;
G_pr=absP.*exp(i.*theta);
g_pr=ifft2(ifftshift(G_pr));
absPhase=abs(angle(g_pr));
maxPh=max(max(absPhase));
minPh=min(min(absPhase));
g_pr(absPhase>=(minPh+0.2*(maxPh-minPh)))=0;
g_pr=real(g_pr);
gg=255*g_pr/(max(max(g_pr)));
figure(1),imshow(uint8(gg)); title(num2str(k))
G=fftshift(fft2(g_pr));
G=G./abs(G);
theta=angle(G);
end
The first theta is the phase of my model image (angle(model)) However, this code diverges instead of converge, Does someone knows why?
Thank you
  댓글 수: 2
Image Analyst
Image Analyst 2015년 9월 27일
You haven't given us enough code to even run your snippet that you posted here. Can't you step through it with the debugger to find out why?
maria
maria 2015년 9월 28일
Gerchberg–Saxton algorithm is made in four steps:
  • step 1: Fourier transform of the model
  • step 2: Replace the modulus of the model-FT by the signal acquired
  • step 3: Fourier-inverse step 2
  • step 4: Create a new model with modulus of the FT-signal and the phase is step 3. Am I right?Since yesterday I have simplified a lot my code to find the mistake. So now it looks like:
model=zeros(150);
model(5:20, 20:121)=1;
model(24:140, 40:50)=1;
model(24:140, 85:97)=1;
figure(1);imagesc(model); colormap(gray)
DS=model;
model=2*pi.*rand(150)-pi;
pi_signal=double(imread('pi.bmp'));
pi_signal=rgb2gray(pi_signal);
pi_signal=imresize(pi_signal, [150 150]);
j=fftshift(fft2(pi_signal));
j=abs(j)/(max(max(abs(j))));
j=imadjust(abs(j), [0; 0.01], [0; 1]);
%
for k=1:1:150;
step1=fftshift(fft2(model));
phase=angle(step1);
Gu=medfilt2(j).*exp(i*phase);
gx=fft2(fftshift(Gu));
model=pi_signal.*exp(i*angle(gx));
figure(7),imagesc(abs(gx)); colormap(gray), title(num2str(k));
end
where "model" is the model in step 1, "pi_signal" is the Fourier Transform of my signal and "j" is my signal.

댓글을 달려면 로그인하십시오.

채택된 답변

PNZ BDCB
PNZ BDCB 2017년 10월 25일
I'm not sure where in your code is the error. The following code works perfectly for me (adopted from wikipedia):
A = fftshift(ifft2(fftshift(Target)));
for i=1:25
B = abs(Source) .* exp(1i*angle(A));
C = fftshift(fft2(fftshift(B)));
D = abs(Target) .* exp(1i*angle(C));
A = fftshift(ifft2(fftshift(D)));
imagesc(abs(C)) %Present current pattern
title(sprintf('%d',i));
pause(0.5)
end
Before running the code, make sure 'Source' contains your input beam, for example:
Source = exp(-1/2*(xx0.^2+yy0.^2)/sigma^2);
And 'Target' contains your requested pattern.
The phase mask can be presented at the end of the for loop:
imagesc(angle(A))
  댓글 수: 1
Isaac Oguntoye
Isaac Oguntoye 2018년 5월 31일
Thanks for the response. Did you consider using your code for a simple image like a dot? Thanks.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Images에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by