Date Conversion

조회 수: 1 (최근 30일)
Syed Abbas
Syed Abbas 2011년 12월 19일
Hi,
I have a <200x1 cell> array which consists of dates read through a text file. The dates are in the format yyyy/mm/dd hh:mm:ss:fff. I want to convert these dates into a matlab recognizable date vector which could then be later used in creating time series objects. I am not sure how to do this.
Thanks,
  댓글 수: 2
Jan
Jan 2011년 12월 19일
Are you sure about the colon before the fractional seconds? Usually there is a dot.
Syed Abbas
Syed Abbas 2011년 12월 19일
Oh, that works now! I mistook the colun for the dot. Thansk a lot for ponting that out.

댓글을 달려면 로그인하십시오.

채택된 답변

Fangjun Jiang
Fangjun Jiang 2011년 12월 19일
datenum()
>> dates={'2011/11/11 11:11:11:111';'2012/12/12 12:12:12:121'}
datenum(dates,'yyyy/mm/dd HH:MM:SS:FFF')
dates =
'2011/11/11 11:11:11:111'
'2012/12/12 12:12:12:121'
ans =
1.0e+005 *
7.3482
7.3522
  댓글 수: 9
Fangjun Jiang
Fangjun Jiang 2011년 12월 19일
Change the last column symbol ":" in the format string to ".". Your data is different than you described in your question. Jan was right. It usually is HH:MM:SS.FFF, not HH:MM:SS:FFF
Fangjun Jiang
Fangjun Jiang 2011년 12월 19일
Or you don't need to specify the format anymore since it is standard.
%%
Dates={'2011/12/15 09:00:00.039';'2011/12/15 09:00:00.039'};
datenum(Dates)

댓글을 달려면 로그인하십시오.

추가 답변 (3개)

Walter Roberson
Walter Roberson 2011년 12월 19일
  댓글 수: 4
Syed Abbas
Syed Abbas 2011년 12월 19일
size shows 1 23 and class shows char
Syed Abbas
Syed Abbas 2011년 12월 19일
I get the following error with cell fun:
Error using cellfun
Input #2 expected to be a cell array, was char instead.

댓글을 달려면 로그인하십시오.


Jose Jeremias Caballero
Jose Jeremias Caballero 2011년 12월 19일
Hello.
>> A={'2011/12/19 13:27:50.890';'2012/12/19 18:49:40.790'}
A =
'2011/12/19 13:27:50.890'
'2012/12/19 18:49:40.790'
>> vector=datevec(A, 'yyyy/mm/dd HH:MM:SS.FFF')
vector =
1.0e+003 *
2.0110 0.0120 0.0190 0.0130 0.0270 0.0509
2.0120 0.0120 0.0190 0.0180 0.0490 0.0408

Jan
Jan 2011년 12월 19일
A less intelligent, but much faster method than DATENUM:
dates = {'2011/11/11 11:11:11.111'; ...
'2012/12/12 12:12:12.121'};
function Vector = myDateConversion(DateCell)
S = sprintf('%s ', DateCell{:});
D = sscanf(S, '%d/%d/%d %d:%d:%f');
Vector = transpose(reshape(D, 6, []));
On Matlab 2009a this is 5 times faster than datevec(dates, 'yyyy/mm/dd HH:MM:SS.FFF'), but datevec is much smarter and converts the '2011/32/12' correctly.
The date topic has been discussed in Mike's blog recently:

카테고리

Help CenterFile Exchange에서 Dates and Time에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by