executing an m-file using a string for calling

조회 수: 19 (최근 30일)
Georgios Mavropoulos
Georgios Mavropoulos 2011년 3월 3일
댓글: Jürgen 2021년 11월 30일
Hello, I am trying to find a way to execute an m-file from a string.
For example I get from a DB return the name myfunc(1,2) as a char and I want to execute the function myfunc.m with the (1,2) as variables. Does anyone have any solution.
Thanx in advance.
Georgios Mavropoulos

채택된 답변

Walter Roberson
Walter Roberson 2011년 3월 3일
%somehow before this, DBString = 'myfunc(1,2)'
eval(DBString)
  댓글 수: 7
Mathijs Franssen
Mathijs Franssen 2021년 2월 18일
Excellent, thanks a million Stephen! Wasn't aware of str2func, first time I've ran into this sort of issue. This helps!
Jürgen
Jürgen 2021년 11월 30일
for me 'Stephens comment' of 28th,jan. 2021 should be worked out more compact and moved to the top-rated answer to the question.
I was also searching for something like (list of) function reference defined during runtime.
The str2fun seems the way to go with respect to all the points in Stephens comment (code analysis, syntax checking, tracing variables, code hints, tab completion, input hints, variable highlighting, debugging, security).

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추가 답변 (4개)

Jan
Jan 2011년 3월 17일
If you call RUN with a string, which contains the path, the file extension .m is removed. Without the path, .m is kept.
mfile = dir('layer*.m');
[trash, name] = fileparts(mfile(1).name);
run(name);
Or:
mfile = dir('layer*.m');
run(fullfile(cd, mfile(1).name));
Note: "mfile(1)" considers, that DIR can find multiple matching files.

Georgios Mavropoulos
Georgios Mavropoulos 2011년 3월 3일
thank you Walter, I tried both of your suggestions and they both worked.
Thanks again for the help.

Dimitris
Dimitris 2011년 3월 15일
I'm trying to do something similar. My output is an .m file. Like this:
mfile = dir('layer*.m')
So, afterwards I want to run the file named layer<something>.m But if I do as you say:
eval(mfile.name)
I get this error:
??? Undefined variable "layer2" or class "layer2.m".
Why is this happening? The file I'm trying to run, layer2.m, is in the current directory.
  댓글 수: 3
Jan
Jan 2011년 3월 17일
RUN removes the file extension only, if the name contains the path:
working: run('C:\MFiles\layer2.m')
failing: run('layer2.m')
I think, this is a bug in RUN: If "script" does not contain a path, "exist(script, 'file')" checks the existence before "evalin('caller', [script, ';'])". But if "script" is an existing file, the file extension let EVALIN fail. "evalin('caller', [s, ';'])" would work. (checked in 2009a)
Jan
Jan 2011년 3월 17일
Bug report is submitted.

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Dimitris
Dimitris 2011년 3월 15일
I tried to use:
run(mfile.name)
but I got the same error:
??? Undefined variable "layer2" or class "layer2.m".
Error in ==> run at 74
evalin('caller',[script ';']);
:S I also tried
run(eval(mfile.name))
with the same results... Thank you for your interest!
  댓글 수: 2
Hayatullahi Adeyemo
Hayatullahi Adeyemo 2017년 11월 12일
You can try using
eval(mfile.name)
Jan
Jan 2017년 11월 12일
@Hayatullahi Adeyemo: The variable "mfile.name" contains the string 'layer2'. The error message produced by run('layer2') means, that there is no function with this name in Matlab's path. Then eval('layer2') will not work also.

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