Extract a non-rectangular region from an image

I have an image whose size is m x n. I also have a vector whose size is m x 1. The elements of the vector are the column numbers in the image where there is a border. I want to extract the image data only to the right of the border. For example, if my image intensity values matrix is
I = [ 0.8308 0.5678 0.4694 0.6020 0.9133 0.9619 0.8001
0.5853 0.0759 0.0119 0.2630 0.1524 0.0046 0.4314
0.5497 0.0540 0.3371 0.6541 0.8258 0.7749 0.9106
0.9172 0.5308 0.1622 0.6892 0.5383 0.8173 0.1818
0.2858 0.7792 0.7943 0.7482 0.9961 0.8687 0.2638
0.7572 0.9340 0.3112 0.4505 0.0782 0.0844 0.1455
0.7537 0.1299 0.5285 0.0838 0.4427 0.3998 0.1361
0.3804 0.5688 0.1656 0.2290 0.1067 0.2599 0.8693 ]
and the vector is:
v = [2; 2; 2; 3; 3; 4; 5; 4];
then I want to create a new image whose values to the right of the border are extracted from the image and to the left of the border are zeros.
I2 = [ 0.0000 0.5678 0.4694 0.6020 0.9133 0.9619 0.8001
0.0000 0.0759 0.0119 0.2630 0.1524 0.0046 0.4314
0.0000 0.0540 0.3371 0.6541 0.8258 0.7749 0.9106
0.0000 0.0000 0.1622 0.6892 0.5383 0.8173 0.1818
0.0000 0.0000 0.7943 0.7482 0.9961 0.8687 0.2638
0.0000 0.0000 0.0000 0.4505 0.0782 0.0844 0.1455
0.0000 0.0000 0.0000 0.0000 0.4427 0.3998 0.1361
0.0000 0.0000 0.0000 0.2290 0.1067 0.2599 0.8693 ]
To develop my algorithm I used a double loop, but now, that I need to do this several thousands of times, I am looking for an efficient way to extract this non-rectangular region from the image.
Any help will be greatly appreciated.

 채택된 답변

Guillaume
Guillaume 2015년 8월 20일
편집: Guillaume 2015년 8월 20일

0 개 추천

I would create a mask using bsxfun that I'd then multiply with the original image:
mask = bsxfun(@ge, 1:size(I, 2), v); %compare row vector 1:size(I, 2) to each element of v and return 1 when it is greater or equal (ge)
I2 = I .* mask
or just on one line:
I2 = I .* bsxfun(@ge, 1:size(I, 2), v)

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Images에 대해 자세히 알아보기

태그

질문:

R S
2015년 8월 20일

댓글:

R S
2015년 8월 20일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by