필터 지우기
필터 지우기

How to select a file based on the filename?

조회 수: 1 (최근 30일)
Rita
Rita 2015년 8월 17일
댓글: Walter Roberson 2015년 8월 19일
Hi, I have several files and I want to just select one based on the maximum number which I could find on the file name. For example I have
abcEFG_1all_0.0675_0.2035.mat
abcEFG_1all_0.087534_0.40354.mat
abcEFG_1all_0.167534_0.603123.mat
and I just want to select and work on this file
abcEFG_1all_0.167534_0.603123.mat
because the numbers are higher than the others. Any suggestion would be appreciated in advance.

채택된 답변

Walter Roberson
Walter Roberson 2015년 8월 17일
  댓글 수: 7
Rita
Rita 2015년 8월 19일
Hi Walter, I stuck in this script I followed your answer but for this one I get the error.I really would appreciate if you could solve my problem. I have
net1_0.2327.mat
net1_0.3425.mat
net2_0.8765.mat
net2_0.6754.mat ,......to net50_0.87654.mat
I would like to get these net1_0.3425.mat net2_0.8765.mat ,.... the max of each net1 to net net50(comparing net1 with net1 and net2 with net2 and so on) I used your script
dinfo = dir('net*.mat');
filenames = {dinfo.name};
parts = regexp(filenames, '_', 'split');
part2 = cellfun(@(C) C{2}, parts, 'Uniform',0);
parts3 = regexp(part2, '.mat', 'split');% to remove mat extension
val2 = str2double(parts3)% I get NaN instead of numbers!
Thanks in advance for your help.
Walter Roberson
Walter Roberson 2015년 8월 19일
Answered in the new Question you opened about this.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Startup and Shutdown에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by