필터 지우기
필터 지우기

logical operations on particular matrix elements

조회 수: 1 (최근 30일)
Christopher
Christopher 2015년 8월 9일
편집: Azzi Abdelmalek 2015년 8월 9일
I have the following code:
numels = 7;
numpts = 3;
C = sparse(numpts,numels)
A = randi(numels,[numpts,1]);
B = rand(numpts,1);
I want to treat the matrix A as an index for the columns of matrix C and move the values of B to their respective columns.
So if we have:
A = [3;3;6];
B = [0.383;0.892;0.192];
Then we should be able to get:
full(C) =
0 0 0.383 0 0 0 0
0 0 0.892 0 0 0 0
0 0 0 0 0 0.192 0
I thought that
C(:,A)=B;
might work, but C(:,A) attempts refers to a matrix and not a set of values.
BTW, I want a logical operation, I don't want to use accumarray or something. It is important that it is fast.
Any help is appreciated.
  댓글 수: 1
Christopher
Christopher 2015년 8월 9일
I've found that I can just find the indices in the sparse matrix and thus use the following:
newA = (A-1).*numpts+(1:numpts)';
C(newA)=B;
However, I've found that using larger matrices of C (required for my implementations), execution of C(newA)=B; is EXTREMELY SLOW.
How can I make this operation faster?

댓글을 달려면 로그인하십시오.

답변 (1개)

Azzi Abdelmalek
Azzi Abdelmalek 2015년 8월 9일
편집: Azzi Abdelmalek 2015년 8월 9일
numels = 7;
numpts = 3;
C = sparse(numpts,numels)
A = [3;3;6];
B = [0.383;0.892;0.192]
idx=sub2ind(size(C),1:numel(A),A')
C(idx)=B
full(C)

카테고리

Help CenterFile Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

태그

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by