Why is the if statement not working?

조회 수: 4 (최근 30일)
tash7827
tash7827 2015년 8월 3일
답변: the cyclist 2015년 8월 3일
this is my code - it is supposed to be a binary array, where the length of time (through the array) that the "1"s are held is determined by "time" - why is the if statement not working based off of the output of "time"?
function cube=cube(exp)
exp=zeros(60,96,10);
time=randi([3 7]);
if time==3
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 8]);
exp(j,jj,rand:rand+2)=1;
end
end
elseif time == 4
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 7]);
exp(j,jj,rand:rand+3)=1;
end
end
elseif time == 5
for j=1:s ize(exp,1);
for jj=1:size(exp,2);
rand=randi([1 6]);
exp(j,jj,rand:rand+4)=1;
end
end
elseif time == 6
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 5]);
exp(j,jj,rand:rand+5)=1;
end
end
elseif time == 7
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 4]);
exp(j,jj,rand:rand+6)=1;
end
end
cube=exp
end
  댓글 수: 1
the cyclist
the cyclist 2015년 8월 3일
One suggestion, aside from trying to solve your main problem, is that you should not be using MATLAB keywords as variable names, because the code may behave in unexpected ways, and also the code simply becomes very confusing (especially for veteran users). In your case, exp and rand should be avoided as variable names.

댓글을 달려면 로그인하십시오.

채택된 답변

the cyclist
the cyclist 2015년 8월 3일
One problem is that in the elseif statement where you check if time == 5, you have
for j=1:s ize(exp,1);
instead of
for j=1:size(exp,1);

추가 답변 (1개)

the cyclist
the cyclist 2015년 8월 3일
편집: the cyclist 2015년 8월 3일
You need
time==3
instead of
time=3
== is the "determine equality" operator. = is the assignment statement.
  댓글 수: 1
tash7827
tash7827 2015년 8월 3일
sorry -- i hadn't realized this was old code - i already have what you suggested and it still is not working - my whole array is still all zero.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Manage Products에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by