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what is 3d plot?

조회 수: 1 (최근 30일)
Rey Kelvin Peralta
Rey Kelvin Peralta 2015년 7월 25일
댓글: Rena Berman 2017년 1월 12일
Can anybody help me on how to smooth out edges to make it rounded and fair? i am using MATLAB and i am quite new to this. Thank you.
  댓글 수: 4
Walter Roberson
Walter Roberson 2015년 7월 26일
What is it that you have available to be plotted? Are you working with a rectangular array of data, or do you have a function that you can evaluate to determine additional data points?
Rena Berman
Rena Berman 2017년 1월 12일
(Answers Dev) Restored question.

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답변 (1개)

Image Analyst
Image Analyst 2015년 7월 26일
You can blur the whole thing with
blurredImage = conv2(data, ones(15), 'same');
If you want to blur just the edges and leave the rest as-is, first blur the whole thing, then find the edges in the original image and replace them with the blurred version. Something like (untested):
blurredImage = conv2(data, ones(15), 'same');
stdImage = stdfilt(data, ones(9));
edgeImage = stdImage > 5; % Whatever value works.
output = data; % Initialize
% Now replace edge pixels with blurred ones.
output(edgeImage) = blurredImage(edgeImage);
  댓글 수: 11
Rey Kelvin Peralta
Rey Kelvin Peralta 2015년 7월 28일
when you did it sir, did it smoothen the center piece? can you show me please? thanks you
Walter Roberson
Walter Roberson 2015년 7월 28일
The following discussion refers to the original image, not reduced to .2 of original size. The 2800+ by 4800+ image.
Try using
blurredImage = conv2(data,ones(75,75)./(75*75),'same');
surf(blurredImage, 'edgecolor', 'none')
You might need to play slightly with the 75 to get the best result, but it is more than 70 and less than 80, something pretty close to 75. Maybe 73.
The more obvious texture is approximately 74 pixels apart with a width of about 23 pixels, but there is also a 5-division submesh within each larger square, so roughly every 10 pixels. It appears the coin has been photographed through the mesh, which makes it important to remove the mesh first. I do not know the best way to remove a texture.

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