Quick way to sum array elements based on flag in another array?

Say I have 2 arrays: one with "clean" data, and one that tells me which data gets lost, as indicated by zeros. If an element is lost, it should be added to the next observed element. Anybody got a quick one-or-two-liner to come up with the summed array?
Example:
clean = [1 2 3 4 5 6]
lost = [1 0 3 0 0 6]
desired = [1 5 15]

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Fun question, well asked with example inputs and expected outputs +1

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 채택된 답변

Stephen23
Stephen23 2015년 7월 14일
편집: Stephen23 2015년 7월 14일
Try this:
tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
desired = accumarray(tmp.',clean).'
Tested:
>> clean = [1 2 3 4 5 6];
>> lost = [1 0 3 0 0 6];
>> tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
>> desired = accumarray(tmp.',clean).'
desired =
1 5 15
>> clean = [40 10 50 30 40 10 50 30 40 10 50 30];
>> lost = [40 0 50 30 0 10 0 0 40 10 50 30];
>> tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
>> desired = accumarray(tmp.',clean).'
desired =
40 60 30 50 120 10 50 30

추가 답변 (2개)

Andrei Bobrov
Andrei Bobrov 2015년 7월 14일
편집: Andrei Bobrov 2015년 7월 14일
desired = flip(accumarray(cumsum(lost(end:-1:1)~=0)',clean(end:-1:1)),1)';
or
desired = accumarray(cumsum(xor([0,diff(lost > 0)],lost))',clean)';

댓글 수: 2

Thanks for the help. Try:
clean = [40 10 50 30 40 10 50 30 40 10 50 30];
lost = [40 0 50 30 0 10 0 0 40 10 50 30];
It should give:
desired = [40 60 30 50 120 10 50 30];
Your solution does not.

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accumarray(interp1(find(lost),1:nnz(lost),1:numel(lost),'next')',clean)

댓글 수: 4

Thanks for the help. Try:
clean = [40 10 50 30 40 10 50 30 40 10 50 30];
lost = [40 0 50 30 0 10 0 0 40 10 50 30];
It should give:
desired = [40 60 30 50 120 10 50 30];
Your solution does not.
Yes it does! Well it's transposed but the numbers are correct
clean = [40 10 50 30 40 10 50 30 40 10 50 30];
lost = [40 0 50 30 0 10 0 0 40 10 50 30];
accumarray(interp1(find(lost),1:nnz(lost),1:numel(lost),'next')',clean)
ans =
40
60
30
50
120
10
50
30
You could always transpose the answer with '
Sorry Sean, I must have fat-fingered the test!

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Ted
2015년 7월 14일

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Ted
2015년 7월 15일

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