Find index in each column of a matrix using for

Good evening,

I am attempting to find the index of the last non-NaN for each column in a matrix. I can't really get it to work correctly; instead of giving me a column vector of indices, it sums the indices together in every cell. Here is my code:

xDate=zeros(1,size(forward,2)); % preallocate a vector
xDate=xDate'; % transpose to a column
for i = 1:size(forward,2)
    xDate(i) = find(~isnan(forward),1,'last')
end

I'm sure it is an easy fix; but I've been racking my brain on it for hours now with no solution.

Thanks to all who are generous enough to help.

Answer 1

[Star Strider]

I don’t have your ‘forward’ matrix so this is just a guess.

See if indexing ‘forward’ as well works:

xDate(i) = find(~isnan(forward(:,i)),1,'last')

[Cary]

Beautiful! Thank you very much :)

[Star Strider]

As always, my pleasure!