Conveter a string with space in a number
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A have one vector returned by the function textscan which have spaces inside the numerical string.
E.g.:
' 0 0 , 2 3 '
' 1 2 , 1 5 '
First, a have to substitute the ',' by '.' (it's simple) but how I remove the spaces? Because using str2num in this vector is returned error.
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Stephen23
2020년 8월 26일
편집: Stephen23
2020년 8월 26일
"A have one vector returned by the function textscan which have spaces inside the numerical string."
I am surprised that no one brought up the obvious solution, to fix the (likely) problem at its source by handling the file encoding properly. Then textscan would import the data correctly.
Image Analyst
2020년 8월 26일
Well, someone might have, but the original poster forgot to attach the original text file. That is a common omission. For some reason, many/most posters totally ignore the posting guidelines that they are shown when they post the question, one of which says to attach their data.
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Image Analyst
2015년 6월 20일
It's pretty much the same except that you set it equal to [] instead of a decimal point:
str(str == ' ') = []; % Remove spaces
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Walter Roberson
2015년 6월 20일
cellfun(@(str)str(str~=' '), dataArray, 'Uniform', 0)
Walter Roberson
2015년 6월 20일
cellfun(@(str)str(2:2:end), dataArray, 'Uniform', 0)
in the case where the odd-numbered characters are the blanks.
추가 답변 (1개)
Azzi Abdelmalek
2015년 6월 20일
편집: Azzi Abdelmalek
2015년 6월 20일
s={' 0 0 , 2 3 ';'1 2 , 1 5 '}
a=strrep(s,',','.')
b=strrep(a,' ','')
out=str2double(b)
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