How to extract variables from Character array
조회 수: 4 (최근 30일)
이전 댓글 표시
Is it possible to get variable names from character array of only particular range?
For example, My char array and it looks like below
en:
variable_en1 = expression; variable_en2 += expression;
variable_en3 := expression;
variable_en4++;
variable_en5--;
du:
variable_du1= expression;
variable_du2 := expression
ex:
variable_ex1=0;variable_ex2=1;
variable_ex3 = 2;
I would like to extract only variable_en1 to variable_en5 in one array and variable_ex1 to variable_ex3 in another arry.
I am attaching character array .mat file.
Could you please help me?
댓글 수: 4
Stephen23
2015년 6월 19일
편집: Stephen23
2015년 6월 19일
What are "variables"? The question is not very clear.
You uploaded a .mat file containing one string. There are easy ways to extract parts of a string (particularly indexing or regular expressions), but you have not explained what part of the strings you are interested in. Please give exact examples of the desired output, and an explanation of how these should be identified (e.g. preceding or trailing characters, newline locations, character patterns, etc).
채택된 답변
Stephen23
2015년 6월 19일
편집: Stephen23
2015년 6월 19일
Thank you for editing your question and making it clearer.
You can use regexp to locate these substrings. Here are several different versions using regexpi, which I tested on your sample .mat file:
>> regexpi(transDestiLabel,'^[a-z]+(?=\s\S?=)','match','lineanchors')
ans =
'a' 'b' 'c' 'd' 'e' 'f' 'g' 'h'
>> regexpi(transDestiLabel,'^[a-z]+(?=+|-)','match','lineanchors')
ans =
'i' 'j'
>> regexpi(transDestiLabel,'^[a-z]+(?=\s\S?=|+|-)','match','lineanchors')
ans =
'a' 'b' 'c' 'd' 'e' 'f' 'g' 'h' 'i' 'j'
The sample file:
댓글 수: 12
Stephen23
2015년 7월 8일
If you want to play around with regular expressions, try using my FEX submission, which lets you interactively build regular expressions and check them on a piece of text:
and keep reading this and trying examples until it all makes sense:
Lets break down the regular expression:
(?<=\s|;|\:)\w+(?=(\s\S?)?(+|-|\:)?=)
(?<=\s|;|\:) % preceded by whitespace, ; or :
\w+ % any alphanumeric word
(?= % followed by...
(\s\S?)? % maybe whitespace + non-whitepsace
(+|-|\:)? % maybe +, - or :
=) % equals sign
Hmmm... it seems like the \S? is not really required.
As I noted in an earlier comment the reasons this regular expression is so complicated is because the file format is a complete mess. If you can tidy up the file format, then identifying the variables becomes much easier.
Good luck!
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Characters and Strings에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!