Need a quick help on storing words according to lengths with struct

조회 수: 1 (최근 30일)
Given a wordlist in cell array
wordlist={'blues';'rhyme';'armor';'dinosour';'book';'mail'......};
wordstruct=struct;
%%i am not sure how to proceed however it is organised such that the words are between four to 25, and I would like to do something like this,
wordstruct.4L={book mail ....}
wordstruct.5L={blues rhyme.....}
.
.
.
.
.
wordstruct.26L={whateveritisthatmightexist}
I almost given up on finding the right way to do it this way. Any help is very appreciated!

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Fangjun Jiang
Fangjun Jiang 2011년 11월 27일
You have to use wordstruct.L4, wordstruct.L5, etc. as '4L','5L' etc. are not valid name.
cellfun('islength',...) and then a for-loop should getting you there.
wordlist={'blues';'rhyme';'armor';'dinosour';'book';'mail'};
clear wordstruct;
Len=cellfun('length',wordlist);
for L=4:26
wordstruct.(['L',num2str(L)])=wordlist(Len==L);
end
  댓글 수: 4
Fangjun Jiang
Fangjun Jiang 2011년 11월 27일
Sorry, I meant cell2struct(). In fact, it doesn't have to be used. See update.

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