how can i convert hourly data for a year to daily data?
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my data start from 1:1:8760 how can i chnge it to daily data with 365 data instead of 8760
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Ingrid
2015년 6월 3일
depends on what you want to do? How do you want to make the conversion. Do you require daily average, daily maximum, daily minimum, value at noon each day, ....
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Salaheddin Hosseinzadeh
2015년 6월 3일
Hi Abdulla,
You may wanna have a look at reshape() function.
Put your data in a column, (apparently its a vector now)
data = data(:); this is one way to make a single column
Than you can reshape your column to a matrix of 360 X N if you like. However 8760 does not generate an integer if divided by 360, so I suggest you pad your data first of all with required number of zeros.
So finally you will have a 360xN data where N is the number of years (about 25 years of data). But keep in mind you will end up with a Matrix.
Hope this helps.
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Salaheddin Hosseinzadeh
2015년 6월 3일
Abdulla,
I think I forgot that we've 365 days in a year! I confused with 2Pi or 360 degrees! lol
I need to practice the number of finger in one hand, number of days in a month and ... LOL
Anyhow, hope you're problem is solved now that you kindly accepted my answer.
Good luck
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Albatross
2015년 6월 12일
I suspect you want to do something like this:
a=1:1:8760;
b=reshape(a,24,365)'
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