how can i convert hourly data for a year to daily data?

my data start from 1:1:8760 how can i chnge it to daily data with 365 data instead of 8760

[Ingrid]

depends on what you want to do? How do you want to make the conversion. Do you require daily average, daily maximum, daily minimum, value at noon each day, ....

Answer 1

[Salaheddin Hosseinzadeh]

Hi Abdulla,

You may wanna have a look at reshape() function.

Put your data in a column, (apparently its a vector now)

data = data(:); this is one way to make a single column

Than you can reshape your column to a matrix of 360 X N if you like. However 8760 does not generate an integer if divided by 360, so I suggest you pad your data first of all with required number of zeros.

So finally you will have a 360xN data where N is the number of years (about 25 years of data). But keep in mind you will end up with a Matrix.

Hope this helps.

[ABDULLA RAHIL]

daer salaheddin i already put all data in one coulumn matrix and these data for just one year 8760 means the number of hours for this years so why you used 360 instead of 365 days

[Salaheddin Hosseinzadeh]

Abdulla,

I think I forgot that we've 365 days in a year! I confused with 2Pi or 360 degrees! lol

I need to practice the number of finger in one hand, number of days in a month and ... LOL

Anyhow, hope you're problem is solved now that you kindly accepted my answer.

Good luck

[ABDULLA RAHIL]

many thanks for your answer but I am struggling to do that even I tried many times , i will send the file to you and see if it is possible or not

Answer 2

[Albatross]

I suspect you want to do something like this:

a=1:1:8760;
b=reshape(a,24,365)'