subscript indices must either be real positive integers or logicals when using a function in a nested for?
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I use this function in a nested for and I get this error: subscript indices must either be real positive integers or logicals
Zpred = h(Xpred)
where Xpred is a matrix
function zk=h(x)
zk(1,:)=sqrt(900+(x(1,:)-30).^2);
zk(2,:)=x(2,:).*(x(1,:)-30)./zk(1,:)
can anyone help me to find the error
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Joseph Cheng
2015년 5월 28일
function zk=h(x)
zk(1,:)=sqrt(900+(x(1,:)-30).^2);
zk(2,:)=x(2,:).*(x(1,:)-30)./zk(1,:)
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Image Analyst
2015년 5월 28일
I think the FAQ explains it really well: http://matlab.wikia.com/wiki/FAQ#How_do_I_fix_the_error_.22Subscript_indices_must_either_be_real_positive_integers_or_logicals..22.3F
When you're calling this:
Zpred = h(Xpred)
at that point, it thinks h is an array, not a function like you thought.
Your script/function is not called h.m is it? Or else somethere else earlier in your code, you must have used h in a way that created an array called h.
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Joseph Cheng
2015년 5월 28일
편집: Joseph Cheng
2015년 5월 28일
so when i run the code you have:
function zk=h(x)
zk(1,:)=sqrt(900+(x(1,:)-30).^2);
zk(2,:)=x(2,:).*(x(1,:)-30)./zk(1,:);
with the input
h(randi(10,2,1))
i don't get the error. Now with this type of error the fastest thing is for you to use the debugger and solve it. Put a breakpoint at the call, verify the input Xpred is actually what you want, there is no variable or other item already called h, and if everything checks out step inside the function where is the line that the error says it is?
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Joseph Cheng
2015년 5월 28일
편집: Joseph Cheng
2015년 5월 28일
you should not use 'h' to describe a function and a variable. Matlab is not smart enough to understand which one you're trying to use.
Here is an example: if my dog is called Brian and I have a friend called Brian, and I ask you to take Brian outside. You wouldn't not know which one to take out side would you? Call your function another name or use another variable name for h.
*sorry to anyone named Brian. It was the first name i could think of.
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