Write a function called one_per_n that returns the smallest positive integer n for which the sum 1 + 1/2 + 1/3 + … + 1/n , is greater than or equal to x where x is the input argument. Limit the maximum number n of terms in the sum to 10,000 .

 function out=one_per_n(x)
if x>10000
 out=-1;
  %fprintf('-1\n');
else
total=0;
for n=1:x;
total=(total+(1/n));
end
if total>=x
out=total;
%fprintf('%d\n',total);
end
end

[Adam]

What exactly is your question? Just posting some code isn't very useful even if you do also paste a homework question into the title.

Answer 1

[Walter Roberson]

Example:

for K = 1 : 50   %maximum 50 times
  t = f(K);      %some calculation dependent on the counter
  if t >= SomeLimit   %did we reach the limit?
    break;       %Yes! Stop this loop!
  end
end

%now that we got here you need to figure out if you matched what you wanted to match, or if you ran out of iterations
%left as an exercise for the reader

[prasanta sahoo]

Sir,According to your instruction i modified my code but till it is not working,

so i placed here modified code with errorname.

code:-

function out=one_per_n(x)
if x>10000
 out=-1;
 else
total=0;
for n=1:10000;
total=sum(1./n);
if total>=x
    break ;
end
end
out=total;
end

Out Put(Error):-

   Feedback: Your function performed correctly for argument(s) 1

Feedback: Your function made an error for argument(s) 2

      Your solution is _not_ correct.

[Torsten]

function out=one_per_n(x)
total=0;
for n=1:10000
  total=total+1/n;
  if total>=x
    break ;
  end
end
out=n;
end

Best wishes

Torsten.

[Christos Vyzantios]

The solution seems ok but the greater saw us the message:

Problem 5 (one_per_n):
    Feedback: Your function performed correctly for argument(s) 1
    Feedback: Your function performed correctly for argument(s) 2
    Feedback: Your function performed correctly for argument(s) 3
    Feedback: Your function performed correctly for argument(s) 4
    Feedback: Your function performed correctly for argument(s) 8
    Feedback: Your function performed correctly for argument(s) 9
    Feedback: Your function performed correctly for argument(s) 9.7875
    Feedback: Your function performed correctly for argument(s) 9.7876
    Feedback: Your function made an error for argument(s) 9.7877

      Your solution is _not_ correct.

[Walter Roberson]

The problem statement from the title does not define what should happen when 10000 terms is not enough to reach the desired total.

Answer 2

[Chen Li]

function d = holiday(month,day)
if month == 1 && day == 1
    d = true;
elseif month == 7 && day == 4
    d = true;   
elseif month == 12 && day == 25
    d = true;
elseif month == 12 && day == 31
    d = true;    
else
d = false;    
end

This is the code that is based on what you wrote. Now it works!

[Walter Roberson]

Note this refers to the additional question https://www.mathworks.com/matlabcentral/answers/218032-write-a-function-called-one_per_n-that-returns-the-smallest-positive-integer-n-for-which-the-sum-1#answer_244928 not to the original question.

Answer 3

[Jean Araujo]

function out = one_per_n(x)
total=0;
n = 1;
while total < x
total = (total+1/n); 
n = n+1;
end
if n-1 > 10000
out = -1;
else
out = (n-1);
end

[Christos Vyzantios]

Yes it is accepted answer. I had tried as out = n-1 only but it didn'nt work...THANX!!!

[Walter Roberson]

Returning -1 was definitely not in the problem statement from the title of this Question!

Answer 4

[Nava Subedi]

I tried to solve the question.

Write a function called holiday that takes two input arguments called month and day; both are scalar integers representing a month (1-12) and a day (1-31). The function returns a logical true if the specified date is a holiday; if not, it returns false. For the purposes of this exercise, the following dates are considered holidays: January 1st, July 4th, December 25th, and December 31st.

I wrote:

function d = holiday(month, day)

     if (month >= 1 && month <=12) && (day >= 1 && day <= 31)   
          if month == 1 && day == 1
              d = 1   
              fprintf('%d is true! It is a holoday. \n', d);
          end
          if month == 7 && day == 4
              d = 1   
              fprintf('%d is true! It is a holoday. \n', d);
          end
          if month == 12 && day == 25
              d = 1   
              fprintf('%d is true! It is a holoday. \n', d);
          end
          if month == 12 && day == 31
              d = 1    
              fprintf('%d is true! It is a holoday. \n', d);
          end
     else
         d = 0
         fprintf('%d is false! It is not a holoday. \n', d);
  return
     end
      end

But did not work. Where did I do mistake??

[Walter Roberson]

The assignment does not request any printing.

The assignment requires logical true and logical false as outputs, not double precision 1 and double precision 0. Logical true is represented as true and logical false is represented as false

Answer 5

[Jorge Briceño]

Hello Nava,

Maybe you could also try to simplify your code. Here is my example:

function out = holiday (m, d)
if (m==1 && d==1) || (m==7 && d==4)|| (m==12 && d==25)...
      || (m==12 && d==31)
  out=true;
else
  out=false;
end
return;
end