find() function indexing seems confusing

조회 수: 76 (최근 30일)
Zeyuan
Zeyuan 2025년 9월 22일 1:09
댓글: Alexander 2025년 10월 7일 20:46
I am writing the code where I want to find the min distance from each point to cluster and the cluster they are assigned to. A step of the k-means algorithm. So I used the function of find. I am confused because even though I tried to set examples, but I keep finding myself in a loophole.
[s_norm, ind] = sort(norm_x(i,:)); % keep i th rown in ascending order
vec_distance(i) = s_norm(1); % take the smallest distance
index(i) = find(ind == 1);
Here is the example I work with
norm_x(i,:) = [2.5 1.0 0.8 3.2]
[s_norm, ind] = sort(norm_x(i,:))
s_norm = [0.8 1.0 2.5 3.2]
ind = [3 2 1 4]
As a reuslt, find(ind==1) should return "3" but why is my code not running? Please help.
  댓글 수: 6
the cyclist
the cyclist 2025년 9월 22일 13:43
Ah, I only noticed the
[2.5 1.0 0.8 3.2]
and wondered about the 1.0. I had not paid sufficient attention to the sort in there.
Alexander
Alexander 2025년 10월 7일 20:46
Most likely an initialization problem before. Try one of the following:
%Example (also possible with double entries)
i=1;
norm_x(i,:) = [2.5 1.0 0.8 3.2];
% Find first smallest value + first index
[vec_distance(i), index(i)] = min(norm_x(i,:));
% Solution for an array
[vec_distance, index] = min(norm_x, [], 2);
% robust form if you you have double entries or want to find e.g. (ind == 2)
[~, ind] = sort(norm_x(i,:));
rank = zeros(1,numel(ind)); % double
rank(ind) = 1:numel(ind); % Inverse permutation
rank_of_col1 = rank(1) % should result in 3
rank_of_col1 = 3
rank_of_col2 = rank(2) % should result in 2
rank_of_col2 = 2
% Maybe you initialize "ind" incorrectly before? Try this for debugging:
[~, ind] = sort(norm_x(i,:));
class(ind) % -> 'double'
ans = 'double'
find(ind==1,1) % should result in 3
ans = 3
find(ind==2,1) % should result in 2
ans = 2

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Number Theory에 대해 자세히 알아보기

태그

제품


릴리스

R2025b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by