function input arguments error

조회 수: 74 (최근 30일)
Cesar Cardenas
Cesar Cardenas 2025년 8월 29일 0:54
편집: VBBV 2025년 8월 29일 7:28
not sure how to solve this issue with function arguments,
I'm trying to do this to figure out how to return a vector y that contains both solutions: a logical variable isreal indicating whether the results were real (isreal=1) or imaginary (isreal=0). not sure if it would be the right approach.
Any help will be appreciated, thank you
myquad
Not enough input arguments.
Error in myquad (line 3)
D = b^2 - 4*a*c;
^
function [y, isreal] = myquad(a, b, c)
% Calculate the discriminant
D = b^2 - 4*a*c;
% Calculate the two solutions using the quadratic formula
y(1) = (-b + sqrt(D)) / (2*a);
y(2) = (-b - sqrt(D)) / (2*a);
% Check if the solutions are real
isreal = all(isreal(y));
% If the discriminant is negative, the solutions are complex
if D < 0
y = [NaN, NaN]; % Return NaN for complex solutions
isreal = 0; % Set isreal to false
end
end
%In the command window I'm trying to call the function like this;
y = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
disp(isreal); % Output: 1
  댓글 수: 1
VBBV
VBBV 2025년 8월 29일 7:27
편집: VBBV 2025년 8월 29일 7:28
Please check the version of Matlab you are using . In some older version, the function defintions are not allowed before actually calling the function in the script file.

댓글을 달려면 로그인하십시오.

채택된 답변

Torsten
Torsten 2025년 8월 29일 1:05
편집: Torsten 2025년 8월 29일 1:25
Don't use isreal as a variable name: isreal is a MATLAB function that you overwrite this way.
[y, is_real] = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
1 1
disp(is_real); % Output: 1
1
function [y, is_real] = myquad(a, b, c)
D = b^2 - 4*a*c;
if D >=0
is_real = true;
y = [(-b + sqrt(D)) / (2*a),(-b - sqrt(D)) / (2*a)];
else
is_real = false;
y = [NaN, NaN];
end
end
  댓글 수: 4
Cesar Cardenas
Cesar Cardenas 2025년 8월 29일 2:03
function [y, is_real] = myquad(a, b, c)
D = b^2 - 4*a*c;
if D >=0
is_real = true;
y = [(-b + sqrt(D)) / (2*a),(-b - sqrt(D)) / (2*a)];
else
is_real = false;
y = [NaN, NaN];
end
end
[y, is_real] = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
disp(is_real); % Output: 1
Cesar Cardenas
Cesar Cardenas 2025년 8월 29일 2:04
I found my mistake, it works now, thank you

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Matt J
Matt J 2025년 8월 29일 1:04
편집: Matt J 2025년 8월 29일 1:30
Your code uses 'isreal' as both the name of a function and a variable. You can resolve the conflict by renaming the output, e.g.,
[y,isReal] = myquad(1, -2, 1)
y = 1×2
1 1
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
isReal = logical
1
function [y, isReal] = myquad(a, b, c)
% Calculate the discriminant
D = sqrt(b^2 - 4*a*c);
isReal=isreal(D);
if ~isReal, y=nan(1,2); return; end
% Calculate the two solutions using the quadratic formula
y = (-b + [-1,1]*D) / (2*a);
end

카테고리

Help CenterFile Exchange에서 Dates and Time에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by