not sure how to solve this issue with function arguments,
I'm trying to do this to figure out how to return a vector y that contains both solutions: a logical variable isreal indicating whether the results were real (isreal=1) or imaginary (isreal=0). not sure if it would be the right approach.
Any help will be appreciated, thank you
myquad
Not enough input arguments.
Error in myquad (line 3)
D = b^2 - 4*a*c;
^
function [y, isreal] = myquad(a, b, c)
% Calculate the discriminant
D = b^2 - 4*a*c;
% Calculate the two solutions using the quadratic formula
y(1) = (-b + sqrt(D)) / (2*a);
y(2) = (-b - sqrt(D)) / (2*a);
% Check if the solutions are real
isreal = all(isreal(y));
% If the discriminant is negative, the solutions are complex
if D < 0
y = [NaN, NaN]; % Return NaN for complex solutions
isreal = 0; % Set isreal to false
end
end
%In the command window I'm trying to call the function like this;
y = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
disp(isreal); % Output: 1

댓글 수: 1

VBBV
VBBV 2025년 8월 29일
편집: VBBV 2025년 8월 29일
Please check the version of Matlab you are using . In some older version, the function defintions are not allowed before actually calling the function in the script file.

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 채택된 답변

Torsten
Torsten 2025년 8월 29일
편집: Torsten 2025년 8월 29일

0 개 추천

Don't use isreal as a variable name: isreal is a MATLAB function that you overwrite this way.
[y, is_real] = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
1 1
disp(is_real); % Output: 1
1
function [y, is_real] = myquad(a, b, c)
D = b^2 - 4*a*c;
if D >=0
is_real = true;
y = [(-b + sqrt(D)) / (2*a),(-b - sqrt(D)) / (2*a)];
else
is_real = false;
y = [NaN, NaN];
end
end

댓글 수: 4

Cesar Cardenas
Cesar Cardenas 2025년 8월 29일
Thank you, still getting the same error, sorry, not so good at matlab, can you show how to call the function?
Matt J
Matt J 2025년 8월 29일
편집: Matt J 2025년 8월 29일
@Cesar Cardenas Torsten and I have both run our code for you so you can see how the function is called and that they produce the proper output. Please run your code for us online, so that we can all see it in action.
function [y, is_real] = myquad(a, b, c)
D = b^2 - 4*a*c;
if D >=0
is_real = true;
y = [(-b + sqrt(D)) / (2*a),(-b - sqrt(D)) / (2*a)];
else
is_real = false;
y = [NaN, NaN];
end
end
[y, is_real] = myquad(1, -2, 1);
disp(y); % Output: [1, 1]
disp(is_real); % Output: 1
Cesar Cardenas
Cesar Cardenas 2025년 8월 29일
I found my mistake, it works now, thank you

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추가 답변 (1개)

Matt J
Matt J 2025년 8월 29일
편집: Matt J 2025년 8월 29일

1 개 추천

Your code uses 'isreal' as both the name of a function and a variable. You can resolve the conflict by renaming the output, e.g.,
[y,isReal] = myquad(1, -2, 1)
y = 1×2
1 1
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
isReal = logical
1
function [y, isReal] = myquad(a, b, c)
% Calculate the discriminant
D = sqrt(b^2 - 4*a*c);
isReal=isreal(D);
if ~isReal, y=nan(1,2); return; end
% Calculate the two solutions using the quadratic formula
y = (-b + [-1,1]*D) / (2*a);
end

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