Switching values around in a matrix

조회 수: 13 (최근 30일)
Scott Banks
Scott Banks 2025년 8월 1일
댓글: dpb 2025년 8월 2일
Hi,
Say I have a 5 by 2 matrix in the form:
A = [2 5; 9 7; 10 2; 3 2; 1 9]
A = 5×2
2 5 9 7 10 2 3 2 1 9
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And I want to make a 10 by 1 matrix from these values so that I get:
B = [2;5;9;7;10;2;3;2;1;9]
B = 10×1
2 5 9 7 10 2 3 2 1 9
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How would I do this?
I know there is a probably a simple fix, but I haven't been able to do it.
Many thanks,
Scott

채택된 답변

Matt J
Matt J 2025년 8월 1일
A = [2 5; 9 7; 10 2; 3 2; 1 9];
B([1:2:10,2:2:10],1)=A(:)
B = 10×1
2 5 9 7 10 2 3 2 1 9
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  댓글 수: 3
Scott Banks
Scott Banks 2025년 8월 2일
Thanks, guys
dpb
dpb 2025년 8월 2일
@Scott Banks, you're free to choose the solution you wish, but I'm curious why you chose the direct indexing solution over the generic one?
As I noted, it does illustrate using vectors as indices in MATLAB which is a powerful tool/feature and is sometimes invaluable, but the other code is general for any size array rather than only working for the specific case and more difficult to code generically (as my other tongue-in-cheek examples illustrate).
Again, just wondering what was your thinking here? Did my response need more amplification beyond the comments?

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dpb
dpb 2025년 8월 1일
편집: dpb 2025년 8월 1일
A = [2 5; 9 7; 10 2; 3 2; 1 9];
% option A
B=A.'; B=B(:) % B=A.'(:); is invalid MATLAB syntax, unfortunately. (Octave allows this in at least some contexts)
B = 10×1
2 5 9 7 10 2 3 2 1 9
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% option B
B=reshape(A.',[],1) % how to implement the above wanted but unallowable syntax...
B = 10×1
2 5 9 7 10 2 3 2 1 9
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The key is to recognize need to transpose to get in needed/wanted column order first...

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