Lagrange interpolation-question on the logic

The following code for calculating the Lagrange interpolation is working, but I have a question: why have we placed the sum after the j-counter not before it ends? wouldn't the fx for the same i and different j overwrite?

Here is the code-I hope it's readable now-:

    % function calculated_value = Lagrange (x,y,xx)
n = length(x);  % Total number of values in x matrix
sum=0; % Initial summation gues
for i=1:n
fx=y(i); % Putting ith value as function value
for j=1:n
  if i ~= j
    fx= fx*(xx-x(j))/(x(i)-x(j)) % Calculating the products
    end
    % end
 sum =sum+fx; % Adding fx values
end
calculated_value = sum;

Answer 1

[Torsten]

First you must build the complete product, then you can add.

Best wishes

Torsten.