Calculated NCA Parameters don't match provided data

조회 수: 2 (최근 30일)
Alexis
Alexis 2025년 6월 17일
답변: Charu 2025년 6월 19일
I am using the sbionca function to compute the NCA Parameters but am getting outputs that don't match the data I've provided. The Cmax/Tmax that is calculated is the first peak observed rather than the maximum concentration observed over the timeframe. How can I fix this?

채택된 답변

Charu
Charu 2025년 6월 19일
Hello,
You're correct in identifying that the sbionca function in MATLAB calculates Cmax and Tmax based on noncompartmental analysis (NCA), which by default considers only the first occurrence of the maximum concentration for Cmax/Tmax.
In your case, because it’s multiple dosing, the concentration profile has multiple peaks, and sbionca is taking the first of those as Cmax”, even though there is a higher peak later.
One workaround that can be used is manually compute Cmax and Tmax:
[maxConc, idx] = max(concentrationData);
Tmax = timeData(idx);
fprintf('True Cmax: %.2f at Tmax: %.2f hours\n', maxConc, Tmax);
The best practice for repeated dosing is to use steady state Cmax or to compute Cmax of the final dose.
Here is the output for the sample data I used along with manual computation of Cmax and Tmax.
Hope this helps!

추가 답변 (1개)

Jacob Mathew
Jacob Mathew 2025년 6월 19일
Hey Alexis,
In the documentation, the Non Compartmental Analysis notes that for Sparse Multiple Dosing, "concentration data is collected from multiple individuals at each time point and then averaged to calculate NCA parameters for each group instead". You can reference the documentation below:
In the NCA parameters screenshot you have provided, there are only 14 datapoints present which could be the reason the algorithm fails to identify the correct peak. The NCA example in the documentation plots a graph with much higher number of datapoints.

카테고리

Help CenterFile Exchange에서 Import Data에 대해 자세히 알아보기

제품


릴리스

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by