Merging multiple dictionaries with cell arrays

조회 수: 9 (최근 30일)
James
James 2025년 6월 3일
편집: Stephen23 2025년 6월 3일
How can one merge multiple dictionaries A and B with cell arrays to get C. Ideally, with some warning for clashes.
A = dictionary( ...
{ ...
"type", ...
"value" ...
}, ...
{...
"temporary", ...
1 ...
} ...
)
A = dictionary (cell --> cell) with 2 entries: {["type"]} --> {["temporary"]} {["value"]} --> {[1]}
B = dictionary( ...
{ ...
"color" ...
}, ...
{...
"blue" ...
} ...
)
B = dictionary (cell --> cell) with 1 entry: {["color"]} --> {["blue"]}
C = dictionary( ...
{ ...
"type", ...
"value", ...
"color" ...
}, ...
{...
"temporary", ...
1, ...
"blue" ...
} ...
)
C = dictionary (cell --> cell) with 3 entries: {["type"]} --> {["temporary"]} {["value"]} --> {[1]} {["color"]} --> {["blue"]}

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Stephen23
Stephen23 2025년 6월 3일
편집: Stephen23 2025년 6월 3일
A = dictionary({"type","value"},{"temporary",1});
B = dictionary({"color"},{"blue"});
If you want to create a new merged dictionary without modifying the originals:
C = dictionary(A.keys, A.values);
C(B.keys) = B.values
C = dictionary (cell --> cell) with 3 entries: {["type"]} --> {["temporary"]} {["value"]} --> {[1]} {["color"]} --> {["blue"]}
If you can modify one of the original dictionaries:
A(B.keys) = B.values
A = dictionary (cell --> cell) with 3 entries: {["type"]} --> {["temporary"]} {["value"]} --> {[1]} {["color"]} --> {["blue"]}
You would have to experiment to find out how it behaves with duplicate keys.

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